40x^2-49x-24=0

Solution for 40x^2-49x-24=0 equation:

40x^2-49x-24=0

a = 40; b = -49; c = -24;
Δ = b2-4ac
Δ = -492-4·40·(-24)
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6241}=79$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-79}{2*40}=\frac{-30}{80}
=-3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+79}{2*40}=\frac{128}{80}
=1+3/5
$